Your reasoning is correct, but the proposal is not. Let me give you an example so you may find the flaw yourself:
You have two people with 2 different dices. One roll 100 numbers, the other 90. But you do not know which numbers were taken off from the 90 faces dice. They can only roll once a day. If you need to prove the dices are different using only the data, how many tries do you need?
1-2 month is about 60 tries. Even if they have the luck to get only different numbers, each getting 60 different number proves anything? Probability states that the 100 one could actually roll more repeat numbers just by chance. So in a limited pool you can think that clearly he is the one will lesser options.
So how many tries do I need to know for sure all the 10 numbers missing in the 90 face dice? There’s no right answer, this is probability, you can get it in 90 tries or 2 billion tries. You can literally spend your whole life throwing that dice and never get 90 different results; unlikely yes, impossible no.
Now imagine you have no idea how your dice looks like, how many faces it has, how many options and possibilities, you only see the results. How many tries do you need to understand what’s happening? A ■■■■ load.
Two months, 60 tries is nothing, absolutely nothing. In 60 tries C can get better loot. The more alike the two “dices” are the more try you need for their difference show in the data. A 1-100 and 1-99 dice has VERY similar data, that 1 number missing will barely show. You need a lot of tries to stress that little diference and make it visible.
I said it already, you guys don’t seem to get the magnitude of the situations. You need thousands of tries in the same EXACT tier loot for years. That’s not a exaggeration, and my example were a dice with 100 sides, so that things has minimal 1% chance, but the probability that some might be 0,x% chance is very high, the dice could have a thousand faces or more. We don’t know, we would have to keep rolling until the data would be stable.